Shell Scripting : To Print the Arguments Passed along with the name of Script - 08

This Shell Script prints the Command line Arguments passed, along with the name of Script

Program Code:

#!/bin/bash
#This is Program that prints the Arguments Passed along with the name of  Script

if [ $# != 2 ]
then
 echo " The usage : You must need to passed 3 Arguments"
 exit 0
fi

echo " This will print the Arguments you've been passed to this Script : "
echo " The total Number of Arguments you've passed is : $# "
echo " The name of the Script : $0"
echo " The First Argument is : $1"
echo " The Second Argument is : $2"

Program Output:

 ./filename.sh  <FirstCommand>  <SecondCommand>