Python - WAP to Check if a Number is Palindrome or Not in Python - 06
Source Code:
#!/usr/bin/python3 while True: num = int(input("Enter a Number : ")) rev = 0 n = num while (num > 0): rem = num % 10 rev = rev * 10 + rem num = num // 10 if (rev == n): print ("Num '%d', is a Palindrome!" % (n)) else: print ("Num '%d', is Not a Palindrome!" % (n)) print ("- Codegig.org") if (input("To Continue ['y'/n] ")) == 'y': continue else: break
Program Output:
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