Python - WAP to Check if a Number is Palindrome or Not in Python - 06
Source Code:
#!/usr/bin/python3
while True:
num = int(input("Enter a Number : "))
rev = 0
n = num
while (num > 0):
rem = num % 10
rev = rev * 10 + rem
num = num // 10
if (rev == n):
print ("Num '%d', is a Palindrome!" % (n))
else:
print ("Num '%d', is Not a Palindrome!" % (n))
print ("- Codegig.org")
if (input("To Continue ['y'/n] ")) == 'y':
continue
else:
break
Program Output:
....


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