Python - WAP to determine if a Number is Armstrong in Python - 18
#!/bin/usr/Python3
while True:
print ()
num=int(input(" Enter any number: "))
a=list(map(int,str(num)))
b=list(map(lambda x:x**3,a))
if(sum(b)==num):
print("The Number is an Armstrong Number! ")
else:
print("The Number isn't an Arsmtrong Number! ")
if (input(" To Continue 'y' : ") == 'y'):
continue
else:
break
Program Output:
....


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